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Nastenka7878
@Nastenka7878
July 2022
2
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1.Вычислите:
arccos(cos13)
2, Найдите Область Определения Функции:
y=1/3arcsin4x
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Rechnung
Verified answer
Arccos(cos 13)=13
y=1/3*arcsin(4x)
D(arcsinx)=[-1;1]
D(arcsin(4x))=[-1;1]
D(1/3*arcsin(4x))=[-1/3;1/3]
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nafanya2014
Verified answer
1)По определению
0 ≤ arccos a ≤ π
-1 ≤ a ≤ 1
и arccos(cos α)= α, если 0 ≤ α ≤ π
cos(13)=cos(4π-13) и угол (4π-13) находится в первой четверти, т.е
0 ≤ (4π-13) ≤ π
Поэтому arccos(cos 13)=arccos(cos (4π-13))=4π-13
2) D(arcsin t)=[-1;1]
-1 ≤ 4x ≤ 1
-1/4 ≤ x ≤ 1/4
Ответ. [-1/4; 1/4]
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Answers & Comments
Verified answer
Arccos(cos 13)=13y=1/3*arcsin(4x)
D(arcsinx)=[-1;1]
D(arcsin(4x))=[-1;1]
D(1/3*arcsin(4x))=[-1/3;1/3]
Verified answer
1)По определению0 ≤ arccos a ≤ π
-1 ≤ a ≤ 1
и arccos(cos α)= α, если 0 ≤ α ≤ π
cos(13)=cos(4π-13) и угол (4π-13) находится в первой четверти, т.е
0 ≤ (4π-13) ≤ π
Поэтому arccos(cos 13)=arccos(cos (4π-13))=4π-13
2) D(arcsin t)=[-1;1]
-1 ≤ 4x ≤ 1
-1/4 ≤ x ≤ 1/4
Ответ. [-1/4; 1/4]