Verified answer

Упростить уравнение [tex](\frac{3}{8}a - \frac{2}{3}b^4 )^2[/tex].

Ответ:

[tex](\frac{3}{8}a - \frac{2}{3}b^4 )^2= (\frac{3}{8} a)^2-2*\frac{3}{8} a*\frac{2}{3}b^4+(\frac{2}{3} b^4)^2=\frac{9}{64}a^2- \frac{1}{2}ab^4+ \frac{4}{9} b^8[/tex]

Формула:

[tex](a-b)^2=a^2-2ab+b^2[/tex]

KO: [tex]\frac{9}{64}a^2- \frac{1}{2}ab^4+ \frac{4}{9} b^8[/tex]

Ответ:

[tex] \frac{9}{64} {a}^{2} \frac{1}{2} a {b}^{4} + \frac{4}{9} {b}^{8} [/tex]

Объяснение:

[tex]( \frac{3}{8} a - \frac{2}{3} {b}^{4} {)}^{2} = ( \frac{3}{8} a {)}^{2} - 2 \times \frac{3}{8} a \times \frac{2}{3} {b}^{4} + ( \frac{2}{3} {b}^{4} {)}^{2} = \frac{9}{64} {a}^{2} - 2 \times \frac{3}{8} a \times \frac{2}{3} {b}^{4} + ( \frac{2}{3} {b}^{4} {)}^{2} = \frac{9}{64} {a}^{2} - \frac{1}{2} a {b}^{4} + ( \frac{2}{3} {b}^{4} {)}^{2} = \frac{9}{64} {a}^{2} - \frac{1}{2} a {b}^{4} + \frac{4}{9} {b}^{8} [/tex]