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OpeXRaX
@OpeXRaX
July 2022
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Задать формулой линейную функцию график которой проходит через точку А(6;5) и параллелен графику функции y = -1/3х + 8
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hhdfe228
5=6k+b
y=-1/3x+8
a1||a2=>k=-1/3
5=6*(-1/3)+b
5=-2+b
b=7
итог
Ответ: y=(-1/3)x+7
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Answers & Comments
y=-1/3x+8
a1||a2=>k=-1/3
5=6*(-1/3)+b
5=-2+b
b=7
итог
Ответ: y=(-1/3)x+7