a(n) = a(1) + d(n - 1)
a(n) = a(n - 1) + d
====
a(3) - a(1) = 8
a(2) + a(4) = 14
S(n) = 111
n - ?
a(1) + 2d - a(1) = 8
a(1) + d + a(1) + 3d = 14
2d = 8
2a(1) + 4d = 14
d = 4
a(1) = -1
S(n) = (2a(1) + d(n - 1))/2 *n
222 = (-2 + 4(n - 1))*n
222 = (-2 + 4n - 4))*n
111 = (2n - 3)n
2n^2 - 3n - 111 = 0
D = 9 + 4*2*111 = 897
√897 - решений нетпри таких условиях
a(n) = -1, 3, 7, 11, 15, 19, 23, 27, 31
S(8) = 104
S(9) = 135
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Answers & Comments
a(n) = a(1) + d(n - 1)
a(n) = a(n - 1) + d
====
a(3) - a(1) = 8
a(2) + a(4) = 14
S(n) = 111
n - ?
a(1) + 2d - a(1) = 8
a(1) + d + a(1) + 3d = 14
2d = 8
2a(1) + 4d = 14
d = 4
a(1) = -1
S(n) = (2a(1) + d(n - 1))/2 *n
222 = (-2 + 4(n - 1))*n
222 = (-2 + 4n - 4))*n
111 = (2n - 3)n
2n^2 - 3n - 111 = 0
D = 9 + 4*2*111 = 897
√897 - решений нетпри таких условиях
a(n) = -1, 3, 7, 11, 15, 19, 23, 27, 31
S(8) = 104
S(9) = 135