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володя47
@володя47
August 2022
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(1/9)^x-6(1/3)^x-27≤0 помогите пожалуйсто
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sedinalana
Verified answer
(1/3)^x=a
a²-6a-27≤0
a1+a2=6 U a1*a2=-27
a1=9 U a2=-3
-3≤(1/3)^x≤9
x≥2
x∈[2;∞)
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Verified answer
(1/3)^x=aa²-6a-27≤0
a1+a2=6 U a1*a2=-27
a1=9 U a2=-3
-3≤(1/3)^x≤9
x≥2
x∈[2;∞)