а) f(x)'=((9x+1)(2x-5))' = (18x²-43x-5)' = 36x - 43
б) f(x)'=(4-6x/3x+1)' = (4-2+1)' = (3)' = 0
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а) f(x)'=((9x+1)(2x-5))' = (18x²-43x-5)' = 36x - 43
б) f(x)'=(4-6x/3x+1)' = (4-2+1)' = (3)' = 0