Ответ:
Квадратное уравнение [tex]\bf 3x^2+bx+2=0\ \ ,\ \ x_1=6[/tex] ,
Согласно теореме Виета
[tex]\left\{\begin{array}{l}\bf x_1\cdot x_2=\dfrac{2}{3}\\\bf x_1+x_2=-\dfrac{b}{3}\end{array}\right\ \ \left\{\begin{array}{l}\bf 6\cdot x_2=\dfrac{2}{3}\\\bf 6+x_2=-\dfrac{b}{3}\end{array}\right\ \ \left\{\begin{array}{l}\bf x_2=\dfrac{1}{9}\\\bf 6+\dfrac{1}{9}=-\dfrac{b}{3}\end{array}\right\ \ \left\{\begin{array}{l}\bf x_2=\dfrac{1}{9}\\\bf \dfrac{55}{9}=-\dfrac{b}{3}\end{array}\right[/tex]
[tex]\left\{\begin{array}{l}\bf x_2=\dfrac{1}{9}\\\bf \ b=-\dfrac{3\cdot 55}{9}\end{array}\right\ \ \left\{\begin{array}{l}\bf x_2=\dfrac{1}{9}\\\bf \, b=-\dfrac{55}{3}\end{array}\right[/tex]
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Answers & Comments
Ответ:
Квадратное уравнение [tex]\bf 3x^2+bx+2=0\ \ ,\ \ x_1=6[/tex] ,
Согласно теореме Виета
[tex]\left\{\begin{array}{l}\bf x_1\cdot x_2=\dfrac{2}{3}\\\bf x_1+x_2=-\dfrac{b}{3}\end{array}\right\ \ \left\{\begin{array}{l}\bf 6\cdot x_2=\dfrac{2}{3}\\\bf 6+x_2=-\dfrac{b}{3}\end{array}\right\ \ \left\{\begin{array}{l}\bf x_2=\dfrac{1}{9}\\\bf 6+\dfrac{1}{9}=-\dfrac{b}{3}\end{array}\right\ \ \left\{\begin{array}{l}\bf x_2=\dfrac{1}{9}\\\bf \dfrac{55}{9}=-\dfrac{b}{3}\end{array}\right[/tex]
[tex]\left\{\begin{array}{l}\bf x_2=\dfrac{1}{9}\\\bf \ b=-\dfrac{3\cdot 55}{9}\end{array}\right\ \ \left\{\begin{array}{l}\bf x_2=\dfrac{1}{9}\\\bf \, b=-\dfrac{55}{3}\end{array}\right[/tex]