3x^3-2x^2 в точке с абсциссой x=3...

August 2022 1 10 Report

записать уравнение касательной к графику функции y=1/3x^3-2x^2 в точке с абсциссой x=3

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snow99 Уравнение касательной:
y= f(x0) + f'(x0)*(x-x0)
f(x0) = 1/3 * 3^3 - 2*3^2 = -9
f'(x) = 1/3 * 3x^2-2*2x = x^2-4x
f'(x0) = 3^2-4*3 = -3
y = -9 -3*(x-3) = -3x

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