f(x)=ctg x
x0=-π/4
y=f(xo)+f'(xo) (x-xo)
f(xo)=ctg (-π/4)= tg π/4 =1
f'(xo) = - 1/sin² (-π/4)= -1/cos² π/4 = -1/(√2/2)²=-4/2= -2
y=1-2(x+π/4) = 1-2x-π/2
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
f(x)=ctg x
x0=-π/4
y=f(xo)+f'(xo) (x-xo)
f(xo)=ctg (-π/4)= tg π/4 =1
f'(xo) = - 1/sin² (-π/4)= -1/cos² π/4 = -1/(√2/2)²=-4/2= -2
y=1-2(x+π/4) = 1-2x-π/2