Home
О нас
Products
Services
Регистрация
Войти
Поиск
schutovalesh
@schutovalesh
December 2022
1
6
Report
Найти уровнение касательной к функции
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
fenix6810
y=y(x0)+y'(x0)(x-x0)
ctg'x=-1/sin^2x
ctg'(x0)=-1/sin^2(-П/4)=-2
y(-П/4)=-1
y=-1-2(x+п/4)=-1-2x-п/2
y=-2x-(1+п/2)
1 votes
Thanks 1
More Questions From This User
See All
schutovalesh
May 2023 | 0 Ответы
d8fdf2791cd0a11043ea6018c101a6d9
Answer
schutovalesh
May 2023 | 0 Ответы
dbc3abaa2fd098f5a7bc9264c5482434
Answer
schutovalesh
March 2023 | 0 Ответы
4
Answer
schutovalesh
August 2022 | 0 Ответы
napisat kak kosvennuyu rech dam vsyo chto ugodno proshu pomosh dam 100 bal
Answer
schutovalesh
July 2022 | 0 Ответы
primerne zovi menya ty volya ne zovi v polya a blokobrashenie volyane zovi
Answer
×
Report "Найти уровнение касательной к функции"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
ctg'x=-1/sin^2x
ctg'(x0)=-1/sin^2(-П/4)=-2
y(-П/4)=-1
y=-1-2(x+п/4)=-1-2x-п/2
y=-2x-(1+п/2)