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Nanamiii
@Nanamiii
August 2022
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2sin(П/4+а)*sin(П/4-а)+sin^2 a
Помогите решить. Подробно. С формулами
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artalex74
Используем формулы:
sin(α+β)=sinαcosβ+sinβcosα; sin(α-β)=sinαcosβ-sinβcosα
2 votes
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sedinalana
Sina*sinb=1/2*cos(a-b)-1/2*cos(a+b)
2*1/2*cos(π/4+a-π/4+a)-2*1/2*cos(π/4+a+π/4-a)-sin²a=
=cos2a-cosπ/2+sin²a=cos²a-sin²a-0+sin²a=cos²a
0 votes
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Answers & Comments
sin(α+β)=sinαcosβ+sinβcosα; sin(α-β)=sinαcosβ-sinβcosα
2*1/2*cos(π/4+a-π/4+a)-2*1/2*cos(π/4+a+π/4-a)-sin²a=
=cos2a-cosπ/2+sin²a=cos²a-sin²a-0+sin²a=cos²a