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2001Student
@2001Student
March 2022
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Помогите пожалуйста упростить.
2sin²(п/4 -α)+sin2α
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армения20171
2sin²(π/4-a)+sin2a=1-cos2(π/4-a)+sin2a=
1-cos(π/2-2a)+sin2a=1-sin2a+sin2a=1
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Answers & Comments
1-cos(π/2-2a)+sin2a=1-sin2a+sin2a=1