Ответ:
[tex]1) (5y+4)(5y-4)=(5y)^2-4^2=25y^2-16\\2) (10x-6c)(10x+6c)=(10x)^2-(6c)^2=100x^2-36c^2\\3) (5a+\frac{1}{5} b)^2=(5a)^2+2*5a*\frac{1}{5}b+ (\frac{1}{5} b) ^2=25a^2+2ab+\frac{1}{25}b^2\\ 4) (12a-0,3x)^2=(12a)^2-2*12a*0,3x+(0,3x)^2=144a^2-7,2ax+0,09x^2[/tex]
Объяснение:
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Ответ:
[tex]1) (5y+4)(5y-4)=(5y)^2-4^2=25y^2-16\\2) (10x-6c)(10x+6c)=(10x)^2-(6c)^2=100x^2-36c^2\\3) (5a+\frac{1}{5} b)^2=(5a)^2+2*5a*\frac{1}{5}b+ (\frac{1}{5} b) ^2=25a^2+2ab+\frac{1}{25}b^2\\ 4) (12a-0,3x)^2=(12a)^2-2*12a*0,3x+(0,3x)^2=144a^2-7,2ax+0,09x^2[/tex]
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