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sxgpups
@sxgpups
June 2023
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ПОМОГИТЕ СРОЧНО. 4.138. Вычислите: 1) sin15ºcos7º-cos11°cos 79°-sin4°sin86°; 2)cos17°cos73º-cos13°cos21°-cos4ºcos86º
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christa14
1)sin(15°) cos (7º)-cos(11º) cos (79°)-sin(4º sin (86°)
(sin(45°-30°)cos(7°)-1/2*(cos(-68°)+cos(90°))-sin(4°)sin(86°)
(sin(45°)cos(30°)-cos(45°)sin(30°))*cos (7°)- 1/2*(cos(68°)+0)-sin(4°)sin (86°)
(√2/2*√3/2 - √2/2*1/2)*cos( 7º) - cos (68°)/2- sin(4°)sin(86°)
(√6/4- √2/4)*cos (7º) - cos (68°)/2- sin(4°)sin(86°)
((√6-√2)/4)*cos(7°) cos (68°)/2 - sin(4°) sin (86°)
Ответ: (cos(7°)x√6 - cos(70)*√2)/4- cos (68°)/ 2 -sin (4°)sin (86°)
Альтернативный ответ: 0
2)
2 votes
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(sin(45°-30°)cos(7°)-1/2*(cos(-68°)+cos(90°))-sin(4°)sin(86°)
(sin(45°)cos(30°)-cos(45°)sin(30°))*cos (7°)- 1/2*(cos(68°)+0)-sin(4°)sin (86°)
(√2/2*√3/2 - √2/2*1/2)*cos( 7º) - cos (68°)/2- sin(4°)sin(86°)
(√6/4- √2/4)*cos (7º) - cos (68°)/2- sin(4°)sin(86°)
((√6-√2)/4)*cos(7°) cos (68°)/2 - sin(4°) sin (86°)
Ответ: (cos(7°)x√6 - cos(70)*√2)/4- cos (68°)/ 2 -sin (4°)sin (86°)
Альтернативный ответ: 0
2)