Розв'яжіть нерівність:
а) 4(х–3)+1≥12–3(1–2х)
б) 9–2(5+3х)<4(1–2х)+2х
в) 0,4у–1,2(3у–1)<1,6(1–у)
г) 2,5(х+3)–(1,5–х)>1–1,5х
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