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korotkix
@korotkix
July 2022
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Найдите произведение значений выражения А и В, если А = 2sin270+tg60*ctg90 , B = 4cosП/3+sinП/6*tgП/4
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nafanya2014
Verified answer
sin270°=sin(360°-90°)=-sin90°=-1
tg60°=√3
ctg90°=0
А = 2sin270°+tg60°·ctg90°=2·(-1)+√3·0=-2
cosπ/3=1/2
sinπ/6=1/2
tgπ/4=1
B = 4cosπ/3+(sinπ/6)·(tgπ/4)=4·(1/2)+(1/2)·1=2+(1/2)=2,5
A·B=-2·2,5=-5
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Answers & Comments
Verified answer
sin270°=sin(360°-90°)=-sin90°=-1tg60°=√3
ctg90°=0
А = 2sin270°+tg60°·ctg90°=2·(-1)+√3·0=-2
cosπ/3=1/2
sinπ/6=1/2
tgπ/4=1
B = 4cosπ/3+(sinπ/6)·(tgπ/4)=4·(1/2)+(1/2)·1=2+(1/2)=2,5
A·B=-2·2,5=-5