Решить уравнение*
sin²(2x-П/6)=3/4
sin^2(2x-p/6)=3/4
sin(2x-p/6)=+-sqrt3/2
2x-p/6=+-(-1)^k*p/3+pk
2x=+-(-1)^k*p/3+p/6+pk
x=+-(-1)^k*p/6+p/12+pk/2; k принадлежит Z
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
sin^2(2x-p/6)=3/4
sin(2x-p/6)=+-sqrt3/2
2x-p/6=+-(-1)^k*p/3+pk
2x=+-(-1)^k*p/3+p/6+pk
x=+-(-1)^k*p/6+p/12+pk/2; k принадлежит Z