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BonParito
@BonParito
August 2022
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Решить уравнение:
x/2 = arccos(sinx) (0<x<p/2)
Ответы:
p/6,2p/3,p/3,p/4.
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Answers & Comments
Ivanna2013
arccos(sinx)=pi/2-arcsin(sinx)=pi/2-x.
x/2=pi/2-x
x=pi-2x
3x=pi
x=pi/3
4 votes
Thanks 2
BonParito
ясно а разве нельзя записать в таком виде x/2 = (1 -x^2) корень.
BonParito
А все понял до чего же легкая задача((
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Answers & Comments
x/2=pi/2-x
x=pi-2x
3x=pi
x=pi/3