Відповідь: √x .
Пояснення:
[ ( √x - 3 )/( √x + 3 ) + 12√x/( x - 9 ) ] : [ ( √x + 3 )/( x - 3√x ) ] = √x .
1 ) ( √x - 3 )/( √x + 3 ) + 12√x/( x - 9 ) = [ ( √x - 3 )² + 12√x ]/[ ( √x +
+ 3 )( √x - 3 ) ] = ( x - 6√x + 9 + 12√x )/[ ( √x + 3 )( √x - 3 ) ] =
= ( x + 6√x + 9 )/[ ( √x + 3 )( √x - 3 ) ] = ( √x + 3 )²/[ ( √x + 3 )( √x - 3 )] =
= ( √x + 3 )/( √x - 3 ) ;
2 ) [(√x + 3 )/(√x - 3 ) ] : [ (√x + 3 )/[ √x(√x - 3 ) ] = [( √x + 3 )/( √x - 3 )] X
X [ √x(√x - 3 )/( √x + 3 ) ] = √x .
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Answers & Comments
Відповідь: √x .
Пояснення:
[ ( √x - 3 )/( √x + 3 ) + 12√x/( x - 9 ) ] : [ ( √x + 3 )/( x - 3√x ) ] = √x .
1 ) ( √x - 3 )/( √x + 3 ) + 12√x/( x - 9 ) = [ ( √x - 3 )² + 12√x ]/[ ( √x +
+ 3 )( √x - 3 ) ] = ( x - 6√x + 9 + 12√x )/[ ( √x + 3 )( √x - 3 ) ] =
= ( x + 6√x + 9 )/[ ( √x + 3 )( √x - 3 ) ] = ( √x + 3 )²/[ ( √x + 3 )( √x - 3 )] =
= ( √x + 3 )/( √x - 3 ) ;
2 ) [(√x + 3 )/(√x - 3 ) ] : [ (√x + 3 )/[ √x(√x - 3 ) ] = [( √x + 3 )/( √x - 3 )] X
X [ √x(√x - 3 )/( √x + 3 ) ] = √x .