Ответ:
1) [tex]\displaystyle \bf (8^{x^2})'=2x\cdot8^{x^2}\cdot ln8[/tex]
2) [tex]\displaystyle \bf (tg\;3x\cdot e^{\frac{1}{x} })'=\frac{3e^{\frac{1}{x} }}{cos^23x}-\frac{tg\;3x\cdot e^{\frac{1}{x} }}{x^2}[/tex]
Пошаговое объяснение:
Найти производную:
[tex]\displaystyle \bf 1)\; (8^{x^2})'=[/tex]
[tex]\displaystyle \bf =8^{x^2}\cdot ln\;8\cdot (x^2)'=[/tex]
[tex]\displaystyle \bf =8^{x^2}\cdot ln\;8\cdot 2x^{2-1}=2x\cdot8^{x^2}\cdot ln\;8[/tex]
[tex]\displaystyle \bf (8^{x^2})'=2x\cdot8^{x^2}\cdot ln8[/tex]
[tex]\displaystyle \bf 2)\; (tg\;3x\cdot e^{\frac{1}{x} })'=[/tex]
[tex]\displaystyle \bf =(tg\;3x)'\cdot e^{\frac{1}{x} }+tg\;3x\cdot(e^{\frac{1}{x} })'=[/tex]
[tex]\displaystyle \bf =\frac{(3x)'}{cos^23x} \cdot e^{\frac{1}{x} }+tg\;3x\cdot e^{\frac{1}{x} }\cdot \left(\frac{1}{x\right)'}=\frac{3e^{\frac{1}{x} }}{cos^23x} -\frac{tg\;3x\cdot e^{\frac{1}{x} }}{x^2}[/tex]
[tex]\displaystyle \bf (tg\;3x\cdot e^{\frac{1}{x} })'=\frac{3e^{\frac{1}{x} }}{xos^23x}-\frac{tg\;3x\cdot e^{\frac{1}{x} }}{x^2}[/tex]
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Answers & Comments
Ответ:
1) [tex]\displaystyle \bf (8^{x^2})'=2x\cdot8^{x^2}\cdot ln8[/tex]
2) [tex]\displaystyle \bf (tg\;3x\cdot e^{\frac{1}{x} })'=\frac{3e^{\frac{1}{x} }}{cos^23x}-\frac{tg\;3x\cdot e^{\frac{1}{x} }}{x^2}[/tex]
Пошаговое объяснение:
Найти производную:
[tex]\displaystyle \bf 1)\; (8^{x^2})'=[/tex]
[tex]\displaystyle \bf =8^{x^2}\cdot ln\;8\cdot (x^2)'=[/tex]
[tex]\displaystyle \bf =8^{x^2}\cdot ln\;8\cdot 2x^{2-1}=2x\cdot8^{x^2}\cdot ln\;8[/tex]
[tex]\displaystyle \bf (8^{x^2})'=2x\cdot8^{x^2}\cdot ln8[/tex]
[tex]\displaystyle \bf 2)\; (tg\;3x\cdot e^{\frac{1}{x} })'=[/tex]
[tex]\displaystyle \bf =(tg\;3x)'\cdot e^{\frac{1}{x} }+tg\;3x\cdot(e^{\frac{1}{x} })'=[/tex]
[tex]\displaystyle \bf =\frac{(3x)'}{cos^23x} \cdot e^{\frac{1}{x} }+tg\;3x\cdot e^{\frac{1}{x} }\cdot \left(\frac{1}{x\right)'}=\frac{3e^{\frac{1}{x} }}{cos^23x} -\frac{tg\;3x\cdot e^{\frac{1}{x} }}{x^2}[/tex]
[tex]\displaystyle \bf (tg\;3x\cdot e^{\frac{1}{x} })'=\frac{3e^{\frac{1}{x} }}{xos^23x}-\frac{tg\;3x\cdot e^{\frac{1}{x} }}{x^2}[/tex]