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yulya9696
@yulya9696
August 2021
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4sin2*120градусов - 2cos 600 + корень из 27*tg660 градусов
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Answers & Comments
Inna1969
Точно tg660? потому что в итоге по корнем минус
sqrt - квадрат
4sin(2*120)-2cos600+sqrt(27tg660)=
=
4sin(180+60)-2cos(360+240)+sqrt(27tg(360+300))=
= - 4sin(60)-2cos(240)+sqrt(27tg(300))= - 4sin(60)-2cos(360-120)+sqrt(27tg(360-60)=
= - 4sin(60)-2cos(120)+sqrt(27tg(-60))=- 4sin(60)-2cos(90+30)+sqrt(27tg(-60))=
= - 4sin(60)+2sin(30)+sqrt(27tg(-60))= - 4(sqrt3/2)+2*1/2+sqrt(27*sqrt(-3))=
= - 2sqrt3+1+3sqrt(3*sqrt(-3))=
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Answers & Comments
4sin(2*120)-2cos600+sqrt(27tg660)=
=4sin(180+60)-2cos(360+240)+sqrt(27tg(360+300))=
= - 4sin(60)-2cos(240)+sqrt(27tg(300))= - 4sin(60)-2cos(360-120)+sqrt(27tg(360-60)=
= - 4sin(60)-2cos(120)+sqrt(27tg(-60))=- 4sin(60)-2cos(90+30)+sqrt(27tg(-60))=
= - 4sin(60)+2sin(30)+sqrt(27tg(-60))= - 4(sqrt3/2)+2*1/2+sqrt(27*sqrt(-3))=
= - 2sqrt3+1+3sqrt(3*sqrt(-3))=