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Kubns
@Kubns
July 2022
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4sin^2x-15cos^2x=4sinxcosx
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Удачник66
Verified answer
Делим всё на cos^2(x)
Получаем квадратное уравнение относительно tg(x)
D = 4^2 - 4*4(-15) = 16 + 16*15 = 256 = 16^2
tg x = (4 - 16)/8 = -12/8 = -3/2
x1 = -arctg(3/2) + pi*k
tg x = (4 + 16)/8 = 20/8 = 5/2
x2 = arctg(5/2) + pi*n
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Answers & Comments
Verified answer
Делим всё на cos^2(x)
Получаем квадратное уравнение относительно tg(x)
D = 4^2 - 4*4(-15) = 16 + 16*15 = 256 = 16^2
tg x = (4 - 16)/8 = -12/8 = -3/2
x1 = -arctg(3/2) + pi*k
tg x = (4 + 16)/8 = 20/8 = 5/2
x2 = arctg(5/2) + pi*n