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tor23
@tor23
July 2022
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4sinacosacos2a=sin4a.
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kirichekov
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4sinα*cosα*cos2α=sin4α
4sinα*cosα*cos2α=2*(2*sinα*cosα)*cos2α=2*sin2α*cos2α=sin(2*2α)=sin4α
sin4α=sin4α
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4sinα*cosα*cos2α=sin4α4sinα*cosα*cos2α=2*(2*sinα*cosα)*cos2α=2*sin2α*cos2α=sin(2*2α)=sin4α
sin4α=sin4α