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tor23
@tor23
July 2022
1
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1+cos2a+sin2a/cosa+sina
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MrBoba98
1+cos
²a-sin²a-(2cosa*sina)/cosa+sina=cos²a+sin²a+cos²a+sin²a-2sina+sina=2cos²a-sina
2 votes
Thanks 3
tor23
не квадраты, а двойной угол
MrBoba98
cos2a=cos^2a-sin^2a
MrBoba98
sin2a=2cosa*sina
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