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aleksa132001
@aleksa132001
July 2022
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(4t-3)^2-25t^2=0
помогите решить уравнение
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2и2
Применяем формулу разности квадратов, получаем:
(4t-3)^2-25t^2=0
(4t-3+5t)(4t-3-5t)=0
(9t-3)(-3-t)=0
Каждую скобку приравниваем к нулю:
9t-3=0, t=1/3
-3-t=0
-t=3, t=-3
Ответ:x1=1/3, x2=-3
2 votes
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Answers & Comments
(4t-3)^2-25t^2=0
(4t-3+5t)(4t-3-5t)=0
(9t-3)(-3-t)=0
Каждую скобку приравниваем к нулю:
9t-3=0, t=1/3
-3-t=0
-t=3, t=-3
Ответ:x1=1/3, x2=-3