(8x^3+1)/(2x-1)*(4x^2-4x+1)/(4x^2-2x+1). Created by kostx. algebra-ru

(4x^2-2x+1)...

August 2022 1 16 Report

(8x^3+1)/(2x-1)*(4x^2-4x+1)/(4x^2-2x+1)

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sebrithien

$\sf \dfrac{8x^3+1}{2x-1}\cdot\dfrac{4x^2-4x+1}{4x^2-2x+1}=\dfrac{(2x+1)(4x^2-2x+1)}{2x-1}\cdot\dfrac{(2x-1)^2}{4x^2-2x+1}=\\\\\\ \sf =(2x+1)(2x-1)=(2x)^2-1^2=\bold{4x^2-1}$

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dany tochki sm3 d41 f24izvestno chto cddf najdite m0f03e5c14394a388bc9a11af2729635d 637

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