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sirniks2012
@sirniks2012
July 2022
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1/x-1/y=3/4
xy=2
это система
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Матов
Verified answer
Умножим второе на первое
xy * (1/x -1/y) = 2* 3/4
y - x = 3/2 =1.5
y = 1.5+x
подставим во второе
x(1.5+x)=2
1.5x +x^2 = 2
x^2 +1.5x -2 =0
умножим на 2
2x^2 +3x -4 =0
D = (-3)^2 - 4*2*-4 = 9 +32 = 41
x1 = 1/4 *(-3 -√41)
x2 = 1/4 *(-3 +√41)
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Answers & Comments
Verified answer
Умножим второе на первоеxy * (1/x -1/y) = 2* 3/4
y - x = 3/2 =1.5
y = 1.5+x
подставим во второе
x(1.5+x)=2
1.5x +x^2 = 2
x^2 +1.5x -2 =0
умножим на 2
2x^2 +3x -4 =0
D = (-3)^2 - 4*2*-4 = 9 +32 = 41
x1 = 1/4 *(-3 -√41)
x2 = 1/4 *(-3 +√41)