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Ateo
@Ateo
June 2022
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4y(y+3)-(y+4)^2
10(1-x)^2+20x
(y-4)(y+4)-(y-3)^2
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Ртуть3
4y(y+3)-(y+4)^2=4y^2+12y-(y^2-8y+16)=3y^2+4y-16
10(1-x)^2+20x=10(1-2x+x^2)+20x=10x^2+10
(y-4)(y+4)-(y-3)^2=y^2-16-(y^2-6y+9)=6y-25
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Answers & Comments
10(1-x)^2+20x=10(1-2x+x^2)+20x=10x^2+10
(y-4)(y+4)-(y-3)^2=y^2-16-(y^2-6y+9)=6y-25