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aitmuhammed2011
@aitmuhammed2011
June 2023
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На плоскости даны точки А(5;-2) и В(-7;3). Найдите длину отрезка АВ по координатам концов.
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zmeura1204
Verified answer
Ответ:
АВ=13
Решение:
АВ=√((Хв-Ха)²+(Ув-Уа)²)=
=√((-7-5)²+(3+2)²)=√((-12)²+5²)=
=√(144+25)=√169=13
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Answers & Comments
Verified answer
Ответ:АВ=13
Решение:
АВ=√((Хв-Ха)²+(Ув-Уа)²)=
=√((-7-5)²+(3+2)²)=√((-12)²+5²)=
=√(144+25)=√169=13