Ответ:
1/2
Объяснение:
[tex] \frac{(a - 3)(a - 3) - (a + 3)(a + 3)}{(a + 3)(a - 3)} = \frac{ {a}^{2} - 6a + 9 - ( {a}^{2} + 6a + 9) }{a^{2} - 9} = \frac{ - 12a}{ {a}^{2} - 9 } \times \frac{9 - {a}^{2} }{24a} = \frac{ - 12a}{ {a}^{2} - 9 } \times \frac{ - ( {a}^{2} - 9) }{24a} = \frac{12a}{24a} = \frac{1}{2} [/tex]
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Answers & Comments
Ответ:
1/2
Объяснение:
Ответ:
[tex] \frac{(a - 3)(a - 3) - (a + 3)(a + 3)}{(a + 3)(a - 3)} = \frac{ {a}^{2} - 6a + 9 - ( {a}^{2} + 6a + 9) }{a^{2} - 9} = \frac{ - 12a}{ {a}^{2} - 9 } \times \frac{9 - {a}^{2} }{24a} = \frac{ - 12a}{ {a}^{2} - 9 } \times \frac{ - ( {a}^{2} - 9) }{24a} = \frac{12a}{24a} = \frac{1}{2} [/tex]