Ответ: tanA=-4/3.
Объяснение:
[tex]\displaystyle\\sinA=\frac{4}{5}=0,8 \ \ \ \ \ \ 90^0 < A < 180^0\ \ \ \ \ \ tanA=?\\\\sin^2A+cos^2A=1\\\\cos^2A=1-sin^2A\\\\cos^2A=1-(0,8)^2=1-0,64=0,36.\\\\cosA=б\sqrt{0,36} =б0,6\\\\90^0 < A < 180^0\ \ \ \ \Rightarrow\\\\cos=-0,6.\\\\tanA=\frac{sinA}{cosA} =\frac{0,8}{-0,6} =\frac{8}{-6}=-\frac{4}{3} .[/tex]
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Ответ: tanA=-4/3.
Объяснение:
[tex]\displaystyle\\sinA=\frac{4}{5}=0,8 \ \ \ \ \ \ 90^0 < A < 180^0\ \ \ \ \ \ tanA=?\\\\sin^2A+cos^2A=1\\\\cos^2A=1-sin^2A\\\\cos^2A=1-(0,8)^2=1-0,64=0,36.\\\\cosA=б\sqrt{0,36} =б0,6\\\\90^0 < A < 180^0\ \ \ \ \Rightarrow\\\\cos=-0,6.\\\\tanA=\frac{sinA}{cosA} =\frac{0,8}{-0,6} =\frac{8}{-6}=-\frac{4}{3} .[/tex]