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oborinamascha
@oborinamascha
July 2022
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Помогите с тригонометрией! Срочно нужно!
Найдите sin(a+b), если sin a = 3/5, cos b = -3/5 и a принадлежит 1 четверти, b принадлежит 3 четверти.
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sedinalana
Verified answer
Sina=3/5⇒cosa=√(1-sin²a)=√(1-9/25)=√(16/25)=4/5
cosb=-3/5⇒sinb=-√(1-cos²b)=-√(1-9/25)=-4/5
sin(a+b)=sinacosb+cosasinb=3/5*(-3/5)+4/5*(-4/5)=-9/25-16/25=-25/25=-1
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Answers & Comments
Verified answer
Sina=3/5⇒cosa=√(1-sin²a)=√(1-9/25)=√(16/25)=4/5cosb=-3/5⇒sinb=-√(1-cos²b)=-√(1-9/25)=-4/5
sin(a+b)=sinacosb+cosasinb=3/5*(-3/5)+4/5*(-4/5)=-9/25-16/25=-25/25=-1