Verified answer

Ответ:

дано

m(C6H6) = 15.6 g

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m(C6H5CL) - ?

C6H6 + CL2-->C6H5CL + HCL

M(C6H6) = 78 g/mol

n(C6H6) = m / M  =15.6 / 78 = 0.2 mol

n(C6H6) = n(C6H5CL)

M(C6H5CL) = 112.5 g/mol

m(C6H5CL) = n*M = 0.2  * 112.2 = 22.5 g

ответ 22.5 гр

2)

дано

V(CL2) = 44.8 L

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m(C6H4CL2) - ?

C6H6 + CL2-->C6H4CL2 + H2

n(CL2) = V(CL2) / Vm = 44.8 / 22.4 = 2 mol

n(CL2)  = n(C6H4CL2) = 2 mol

M(C6H4CL2) = 147 g/mol

m(C6H4CL2) = n*M = 2*147 = 294 g

ответ 294 гр

Объяснение: