[tex] \frac{3x + 5}{ 3} + \frac{2x - 1}{7} = 3 \\ 7(3x + 5) + 3(2x - 1) = 63 \\ 21x + 35 + 6x - 3 = 63 \\ 21x + 6x = 63 - 35 + 3 \\ 27x = 31 \\ x = \frac{31}{27} \\ x = 1 \frac{4}{27} [/tex]
Ответ:
Объяснение:
(3х+5)/3+(2х-1)/7=3(3х+5)*7+(2х-1)*3=3*2121х+35+6х-3=6327х+32=6327х=31
х=31/27
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[tex] \frac{3x + 5}{ 3} + \frac{2x - 1}{7} = 3 \\ 7(3x + 5) + 3(2x - 1) = 63 \\ 21x + 35 + 6x - 3 = 63 \\ 21x + 6x = 63 - 35 + 3 \\ 27x = 31 \\ x = \frac{31}{27} \\ x = 1 \frac{4}{27} [/tex]
Ответ:
Объяснение:
(3х+5)/3+(2х-1)/7=3
(3х+5)*7+(2х-1)*3=3*21
21х+35+6х-3=63
27х+32=63
27х=31
х=31/27