Ответ:
5
Объяснение:
(х-4)*(2х+5)=(х-4)(5х+2)
перенесем все влево и вынесем общую скобку (х-4) за скобку:
(х-4)*(2х+5)-(х-4)(5х+2)=0
(х-4)*(2х+5-5х-2)=0
(х-4)*(3-3х)=0
х-4=0
х=4 -корень уравнения
3-3х=0
3х=3
х=1- корень уравнения
сумма корней уравнения 4+1=5
[tex]\displaystyle\bf\\\Big(x-4\Big)\Big(2x+5\Big)=\Big(x-4\Big) \Big(5x+2\Big)\\\\\\\Big(x-4\Big)\Big(2x+5\Big)-\Big(x-4\Big) \Big(5x+2\Big)=0\\\\\\\Big(x-4\Big)\Big(2x+5-5x-2\Big)=0\\\\\\\Big(x-4\Big)\Big(-3x+3\Big)=0\\\\\\-3\cdot\Big(x-4\Big)\Big(x-1\Big)=0\\\\\\\Big(x-4\Big)\Big(x-1\Big)=0\\\\\\\left[\begin{array}{ccc}x-4=0\\x-1=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =4\\x_{2} =1\end{array}\right\\\\\\x_{1} + x_{2} =4+1=5\\\\\\Otvet \ : \ 5[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
5
Объяснение:
(х-4)*(2х+5)=(х-4)(5х+2)
перенесем все влево и вынесем общую скобку (х-4) за скобку:
(х-4)*(2х+5)-(х-4)(5х+2)=0
(х-4)*(2х+5-5х-2)=0
(х-4)*(3-3х)=0
х-4=0
х=4 -корень уравнения
3-3х=0
3х=3
х=1- корень уравнения
сумма корней уравнения 4+1=5
Verified answer
[tex]\displaystyle\bf\\\Big(x-4\Big)\Big(2x+5\Big)=\Big(x-4\Big) \Big(5x+2\Big)\\\\\\\Big(x-4\Big)\Big(2x+5\Big)-\Big(x-4\Big) \Big(5x+2\Big)=0\\\\\\\Big(x-4\Big)\Big(2x+5-5x-2\Big)=0\\\\\\\Big(x-4\Big)\Big(-3x+3\Big)=0\\\\\\-3\cdot\Big(x-4\Big)\Big(x-1\Big)=0\\\\\\\Big(x-4\Big)\Big(x-1\Big)=0\\\\\\\left[\begin{array}{ccc}x-4=0\\x-1=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =4\\x_{2} =1\end{array}\right\\\\\\x_{1} + x_{2} =4+1=5\\\\\\Otvet \ : \ 5[/tex]