Объяснение:

Для начала вспомним как преобразовать отрицательную степень в дробь:

[tex] {x}^{ - n} = \frac{1}{ {x}^{n} } [/tex]

1)а)

[tex]7 {m}^{ - 6} = 7 \times \frac{1}{ {m}^{6} } = \frac{7}{ {m}^{6} } [/tex]

б)

[tex]2 {(ab)}^{ - 1} = 2 \times \frac{1}{ab} = \frac{2}{ab} [/tex]

в)

[tex]11 {(x + 3)}^{ - 3} = 11 \times \frac{1}{{(x + 3)}^{3} } = \frac{11}{ {(x + 3)}^{3} } [/tex]

д)

[tex]9 {a}^{3} {b}^{ - 4} {c}^{0} = 9 {a}^{3} \times \frac{1}{ {b}^{4} } \times 1 = \frac{9 {a}^{3} }{ {b}^{4} } [/tex]

2)а)

[tex] {a}^{ - 2} + {b}^{ - 1} = \frac{1}{ {a}^{2} } + \frac{1}{b} = \frac{ {a}^{2} + b }{ {a}^{2} b} [/tex]

б)

[tex] {x}^{0} + {x}^{ - 3} = 1 + \frac{1}{ {x}^{3} } = \frac{ {x}^{3} + 1 }{ {x}^{3} } [/tex]

в)

[tex]a + {b}^{ - 3} = a + \frac{1}{ {b}^{3} } = \frac{a {b}^{3} + 1}{ {b}^{3} } [/tex]

д)

[tex]x {y}^{ - 3} - {x}^{ - 1} {y}^{ 2} = x \times \frac{1}{ {y}^{3} } - \frac{1}{x} \times {y}^{2} = \frac{x}{ {y}^{3} } - \frac{ {y}^{2} }{x} = \frac{ {x}^{2} - {y}^{5} }{ {y}^{3} x} [/tex]