n(NH3) = m(NH3) : M(NH3) = 34 : 17 = 2 моль
V(NH3) = n(NH3) × Vm = 2 × 22,4 = 44,8 л
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n(NH3) = m(NH3) : M(NH3) = 34 : 17 = 2 моль
V(NH3) = n(NH3) × Vm = 2 × 22,4 = 44,8 л