Ответ:
б) (b-c)³=b³-3b²c+3bc²-b³
Б)(b-2)³=b³-2b²2+3b2²-b³=b³-4b²+12b-b³
(10+c)³=10³+3×10²c+3×10c²+c³=1000+300c+30c²+c³
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Ответ:
б) (b-c)³=b³-3b²c+3bc²-b³
Б)(b-2)³=b³-2b²2+3b2²-b³=b³-4b²+12b-b³
(10+c)³=10³+3×10²c+3×10c²+c³=1000+300c+30c²+c³