Объяснение:
№7
m¹⁵(n⁶)³ / (mn)¹⁷ = m¹⁵n¹⁸ / m¹⁷n¹⁷ = n/(m²)
m = 5; n = 15
n/(m²) = 15/(5²) = 15/25 = 3/5
№8
х¹⁴(у³)⁵ / (ху)¹³ = х¹⁴у¹⁵/х¹³у¹³ = ху¹⁵/у¹³ = ху²
х = 10; у = 7
ху² = 10 * 7² = 10 * 49 = 490
№9
а¹⁶(в⁷)³/(ав)¹⁸ = а¹⁶в²¹/а¹⁸в¹⁸ = а¹⁶в³/а¹⁸ = в³/а²
а = 2; в = 6
в³/а² = 6³/2² = 216/4 = 54
[tex] \frac{ {m}^{15} ( {n}^{6} ) {}^{3} }{(mn) {}^{17} } = \frac{m {}^{15} n {}^{18} }{m {}^{17} n {}^{17} } = \frac{n}{ {m}^{2} } = \\ = \frac{15}{5 {}^{2} } = \frac{15}{25} = \frac{3}{5} = 0.6[/tex]
[tex] \frac{ {x}^{14}(y {}^{3} ) {}^{5} }{(xy) {}^{13} } = \frac{ {x}^{14}y {}^{15} }{x {}^{13} {y}^{13} } = x {y}^{2} = \\ = 10 \times {7}^{2} = 10 \times 49 = 490[/tex]
[tex] \frac{ {a}^{16} (b {}^{7} ) {}^{3} }{(ab) {}^{18} } = \frac{ {a}^{16} {b}^{21} }{ {a}^{18} {b}^{18} } = \frac{ {b}^{3} }{ {a}^{2} } = \\ = \frac{ {6}^{3} }{ {2}^{2} } = \frac{216}{4} = 54[/tex]
Использовались свойства степени:
[tex](x {}^{a} ) {}^{b} = x {}^{ab} \\ (xy) {}^{a} = {x}^{a} \times {y}^{a} [/tex]
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Verified answer
Объяснение:
№7
m¹⁵(n⁶)³ / (mn)¹⁷ = m¹⁵n¹⁸ / m¹⁷n¹⁷ = n/(m²)
m = 5; n = 15
n/(m²) = 15/(5²) = 15/25 = 3/5
№8
х¹⁴(у³)⁵ / (ху)¹³ = х¹⁴у¹⁵/х¹³у¹³ = ху¹⁵/у¹³ = ху²
х = 10; у = 7
ху² = 10 * 7² = 10 * 49 = 490
№9
а¹⁶(в⁷)³/(ав)¹⁸ = а¹⁶в²¹/а¹⁸в¹⁸ = а¹⁶в³/а¹⁸ = в³/а²
а = 2; в = 6
в³/а² = 6³/2² = 216/4 = 54
7)
[tex] \frac{ {m}^{15} ( {n}^{6} ) {}^{3} }{(mn) {}^{17} } = \frac{m {}^{15} n {}^{18} }{m {}^{17} n {}^{17} } = \frac{n}{ {m}^{2} } = \\ = \frac{15}{5 {}^{2} } = \frac{15}{25} = \frac{3}{5} = 0.6[/tex]
8)
[tex] \frac{ {x}^{14}(y {}^{3} ) {}^{5} }{(xy) {}^{13} } = \frac{ {x}^{14}y {}^{15} }{x {}^{13} {y}^{13} } = x {y}^{2} = \\ = 10 \times {7}^{2} = 10 \times 49 = 490[/tex]
9)
[tex] \frac{ {a}^{16} (b {}^{7} ) {}^{3} }{(ab) {}^{18} } = \frac{ {a}^{16} {b}^{21} }{ {a}^{18} {b}^{18} } = \frac{ {b}^{3} }{ {a}^{2} } = \\ = \frac{ {6}^{3} }{ {2}^{2} } = \frac{216}{4} = 54[/tex]
Использовались свойства степени:
[tex](x {}^{a} ) {}^{b} = x {}^{ab} \\ (xy) {}^{a} = {x}^{a} \times {y}^{a} [/tex]