Ответ сверху ^^
Автор: Лоулайт3071.
[tex] \frac{ {x}^{6}y + x {y}^{6} }{5(3y - 2x)} \times \frac{2(2x - 3y)}{ {x}^{5} + {y}^{5 } } = \\ \frac{xy( {x}^{5} + {y}^{5}) \times 2(2x - 3y) }{ - 5(2x - 3y) \times ( {x}^{5} + {y}^{5} )} = \\ - \frac{2xy}{5} = - \frac{2 \times \frac{1}{8} \times (- 8)}{5} = \frac{2}{5} = 0.4[/tex]
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Ответ сверху ^^
Автор: Лоулайт3071.
[tex] \frac{ {x}^{6}y + x {y}^{6} }{5(3y - 2x)} \times \frac{2(2x - 3y)}{ {x}^{5} + {y}^{5 } } = \\ \frac{xy( {x}^{5} + {y}^{5}) \times 2(2x - 3y) }{ - 5(2x - 3y) \times ( {x}^{5} + {y}^{5} )} = \\ - \frac{2xy}{5} = - \frac{2 \times \frac{1}{8} \times (- 8)}{5} = \frac{2}{5} = 0.4[/tex]