[tex] {x}^{2} + 2x - 3 = 0 \\ \\ po \: \: \: teoreme \: \: \: vieta \\ {x}^{2} + bx + c = 0\\ x_{1} + x_{2} = - b\\ x_{1} x_{2} = c \\ \\ x_{1} + x_{2} = - 2 \\ x_{1} x_{2} = - 3 \\ x_{1} = - 3 \\ x_{2} = 1 \\ \\ {ax}^{2} + bx + c = a(x - x_{1})(x - x_{2}) \\ {x}^{2} + 2x - 3 = (x + 3)(x - 1)[/tex]

[tex] \frac{ {x}^{2} + 2x - 3 }{(x + 1) {}^{2} } \leqslant 0 \\ \frac{(x + 3)(x - 1)}{(x + 1) {}^{2} } \leqslant 0 \\ \\ \left \{ {{(x + 3)(x - 1)(x + 1) {}^{2} \leqslant 0 } \atop {x \neq - 1}} \right. \\ \\ + + + [ - 3] - - - ( - 1) - - - [ 1] + + + \\ x \: \epsilon\: [ - 3; \: - 1)U( - 1; \: 1][/tex]