Ответ:

Объяснение:

1)[tex]\left \{ {{3x-9 < } 0\atop {x+2 > 3}} \right= > \left \{ {{3x < 9} \atop {x > 3-2}} \right. = > \left \{ {{x < 3} \atop {x > 1}} \right.[/tex]  x∈(1;3)

2)[tex]\left \{ {{5x-3} \geq 7\atop {2-x\leq 1}} \right.= > \left \{ {{5x\geq 7+3} \atop {-x\leq 1-2}} \right. = > \left \{ {x\geq 2} \atop {x\geq 1}} \right.[/tex] x∈[2;+∝)