Ответ:
1) w = m(р.в.) / m(р-ра) * 100% = 45,5г / 130г * 100% = 35% w(O) = 35%
2) M(CO(NH2)2) = 60г/моль
w(C) = 12 / 60 * 100% = 20%
w(O) = 16 / 60 * 100% = 26,7%
w(N) = 28 / 60 * 100% = 46,7%
w(H) = 4 / 60 * 100% = 6,6%
Объяснение:
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Ответ:
1) w = m(р.в.) / m(р-ра) * 100% = 45,5г / 130г * 100% = 35%
w(O) = 35%
2) M(CO(NH2)2) = 60г/моль
w(C) = 12 / 60 * 100% = 20%
w(O) = 16 / 60 * 100% = 26,7%
w(N) = 28 / 60 * 100% = 46,7%
w(H) = 4 / 60 * 100% = 6,6%
Объяснение: