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nikith1
@nikith1
July 2022
2
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50 БАЛЛОВ решить
cos^2x+6sinx-6=0
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Сhemist
Cos²x+6sinx-6=0
1-sin²x+6sinx-6=0
sin²x-6sinx+5=0
sinx=3±√(9-5) =3±2
1) sinx=5 – нет корней;
2) sinx=1 => x=π/2+2πn, n ε Z.
0 votes
Thanks 3
Yak73
1-sin^2x+6*sinx-6=0
sin^2x-6sinx+5=0
sinx=t
t^2-6*t+5=0
t1=5 t2=1
sinx=5 нет корней (t e [-1;1])
sinx=1
x=pi/2+2pi*k;
1 votes
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Answers & Comments
1-sin²x+6sinx-6=0
sin²x-6sinx+5=0
sinx=3±√(9-5) =3±2
1) sinx=5 – нет корней;
2) sinx=1 => x=π/2+2πn, n ε Z.
sin^2x-6sinx+5=0
sinx=t
t^2-6*t+5=0
t1=5 t2=1
sinx=5 нет корней (t e [-1;1])
sinx=1
x=pi/2+2pi*k;