5^(2x-1)=0,4 × 2^(2x-1). Created by lerros02. algebra-ru

5^(2x-1)=0,4 × 2^(2x-1)...

koshelev32

$5^{2x-1} =0,4*2^{2x-1}\\\\\frac{5^{2x-1} }{2^{2x-1} }=\frac{0,4*2^{2x-1} }{2^{2x-1}};2^{2x-1}\neq0\\\\(\frac{5}{2})^{2x-1}=\frac{2}{5}\\\\(\frac{5}{2})^{2x-1}=(\frac{5}{2})^{-1}\\\\2x-1=-1\\\\2x=0\\\\x=0$

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Universalka

Verified answer

${5}^{2x - 1} = 0.4 \times {2}^{2x - 1 } \\ 1 = \frac{2}{5} \times {2}^{2x - 1 } \div {5}^{2x - 1} \\ 1 = { \frac{2}{5} }^{2x} \\ 2x = 0 \\ x = 0$

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