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zimazar85
@zimazar85
August 2022
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Срочно!!!с Объяснением
195 номер 1/2/3/4/5
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Answers & Comments
1)
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3)![log_{\sqrt[5]{36} }8=log_{6^{2/5} }2^3=\frac{3}{2/5} log_{{6} }2=\frac{15}{2} log_{{6} }2=7,5a](https://tex.z-dn.net/?f=log_%7B%5Csqrt%5B5%5D%7B36%7D%20%20%7D8%3Dlog_%7B6%5E%7B2%2F5%7D%20%20%7D2%5E3%3D%5Cfrac%7B3%7D%7B2%2F5%7D%20log_%7B%7B6%7D%20%7D2%3D%5Cfrac%7B15%7D%7B2%7D%20log_%7B%7B6%7D%20%7D2%3D7%2C5a "log_{\sqrt[5]{36} }8=log_{6^{2/5} }2^3=\frac{3}{2/5} log_{{6} }2=\frac{15}{2} log_{{6} }2=7,5a")
4)![log_{\sqrt[4]{216} }0,125=log_{6^{3/4} }2^{-3}=\frac{-3}{3/4} log_{{6} }2=-4 log_{{6} }2=-4a](https://tex.z-dn.net/?f=log_%7B%5Csqrt%5B4%5D%7B216%7D%20%20%7D0%2C125%3Dlog_%7B6%5E%7B3%2F4%7D%20%20%7D2%5E%7B-3%7D%3D%5Cfrac%7B-3%7D%7B3%2F4%7D%20log_%7B%7B6%7D%20%7D2%3D-4%20log_%7B%7B6%7D%20%7D2%3D-4a "log_{\sqrt[4]{216} }0,125=log_{6^{3/4} }2^{-3}=\frac{-3}{3/4} log_{{6} }2=-4 log_{{6} }2=-4a")
5)