[tex]\displaystyle\bf\\\int\limits^1_ 2 {(6x-2)} \, dx =\Big(6\cdot\frac{x^{2} }{2} -2x\Big)\Big|^{1}_{-2} =\Big(3x^{2} -2x\Big)\Big|^{1} _{-2} =\\\\\\=3\cdot 1^{2} -2\cdot 1-\Big[3\cdot(-2)^{2} -2\cdot(-2)\Big]=3-2-(12+4)=\\\\\\=1-16=-15[/tex]