5_ или

July 2022 1 6 Report

СРОЧНО ПОМОГИТЕ ПОЖАЛУЙСТА!!!! ДАЮ 30 БАЛЛОВ ПОЖАЛУЙСТА!! решите неравенство:
распишите решение

a) 3,8x-5>2 (1,9x+4)

b) 1/3(3x-6)-0,8(x-1)>0,6(2x-3)

c)(9x-2)(4x+1)-(6x-1)²>_-7(x+4)

d)5-2x/4 - 1-x/5<_0
(>_ или <_ - двойные неравенства)

Answers & Comments

Universalka

Verified answer

$\displaystyle\bf\\1)\\\\3,8x-5>2(1,9x+4)\\\\3,8x-5>3,8x+8\\\\3,8x-3,8x>8+5\\\\0\cdot x>13- \ neverno$

Решений нет

$\displaystyle\bf\\2)\\\\\frac{1}{3} \Big(3x-6\Big)-0,8\Big(x-1\Big)>0,6\Big(2x-3\Big)\\\\\\x-2-0,8x+0,8>1,2x-1,8\\\\\\0,2x-1,2x>-1,8+1,2\\\\\\-x>-0,6\\\\\\x$

$\displaystyle\bf\\\frac{5-2x}{4}\cdot 20-\frac{1-x}{5} \cdot 20\leq 0\cdot 20\\\\\\(5-2x)\cdot 5-(1-x)\cdot 4\leq 0\\\\\\25-10x-4+4x\leq 0\\\\\\-6x\leq -21\\\\\\x\geq 3,5\\\\\\Otvet:x\in\Big[3,5 \ ; \ +\infty\Big)$

7 votes Thanks 9

Answers & Comments

Verified answer

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