[tex]\sqrt[]{3x^{2} +5x+8} = 3+x\\(\sqrt[]{3x^{2} +5x+8})^{2} = (3+x)^{2} \\\\ 3x^{2} +5x+8=9+6x+x^{2} \\3x^{2} +5x+8-9-6x-x^{2} =0\\2x^{2} -x-1 =0\\D=b^{2} -4ac=1-4*2(-1)=9\\x_{1-2} =\frac{1(+-)3 }{4} = 1; -0.5[/tex]
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[tex]\sqrt[]{3x^{2} +5x+8} = 3+x\\(\sqrt[]{3x^{2} +5x+8})^{2} = (3+x)^{2} \\\\ 3x^{2} +5x+8=9+6x+x^{2} \\3x^{2} +5x+8-9-6x-x^{2} =0\\2x^{2} -x-1 =0\\D=b^{2} -4ac=1-4*2(-1)=9\\x_{1-2} =\frac{1(+-)3 }{4} = 1; -0.5[/tex]