[tex] {x}^{2} + 28x + 180 = 0 \\ \\ po \: \: \: teoreme \: \: \: vieta \\ {x}^{2} + bx + c = 0\\ x_{1} + x_{2} = - b\\ x_{1} x_{2} = c \\ \\ x_{1} + x_{2} = - 28\\ x_{1} x_{2} = 180\\ x_{1} = - 10 \\ x_{2} = - 18 \\ x_{1} - x_{2} = - 10 - ( - 18) = - 0 + 18 = 8[/tex]

Ответ: 8 ; - 28 ; 180